Chapter 1 - Section 1.1 - Linear Equations - 1.1 Assess Your Understanding - Page 90: 46

$x=\frac{-15}{7}$

$\displaystyle \begin{array}{{>{\displaystyle}l}} We\ have:\ ( x+2)( x-3) =( x+3)^{2}\\ \\ First,\ expand\ all\ brackets:\\ \\ ( x+2)( x-3) =( x+3)^{2}\\ x^{2} -3x+2x-6=x^{2} +6x+9\\ \\ Then\ simplify:\\ x^{2} -x-6=x^{2} +6x+9\\ -6=7x+9\\ 7x=-15\\ x=\frac{-15}{7} \end{array}$