College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Appendix - Graphing Utilities - 1 The Viewing Rectangle - 1 Exercises - Page A2: 9

Answer

See below.

Work Step by Step

As we can see on the figure: $X_{max}=9,X_{min}=3,Y_{max}=10,Y_{min}=2. $ There are 6 sections on the "x-axis", hence $X_{scl}=\frac{X_{max}−X_{min}}{6}=\frac{9-3}{6}=1.$ There are 4 sections on the "y-axis", hence $Y_{scl}=\frac{Y_{max}−Y_{min}}{4}=\frac{10-2}{4}=2.$
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