Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Test - Page R-35: 9

Answer

$\frac{9}{10}$ $\div$ 18 = $\frac{1}{20}$

Work Step by Step

Perform the indicated operation and simplify. $\frac{9}{10}$ $\div$ 18 = $\frac{9}{10\times18}$ = $\frac{9}{180}$ = $\frac{9/9}{180/9}$ = $\frac{1}{20}$ Result: $\frac{1}{20}$
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