## Algebra: A Combined Approach (4th Edition)

$\frac{41}{48}$
1. Find LCD of fractions: The LCD of 12 and 16 is 48. 2. Write as equivalent fractions with denominator of 60. $\frac{11*4}{12*4} - \frac{1*3}{16*3} = \frac{44}{48} - \frac{3}{48}$ 3. Subtract numerators. $\frac{44-3}{48} = \frac{41}{48}$