Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Section R.2 - Fractions - Exercise Set - Page R-16: 48

Answer

$\frac{41}{48}$

Work Step by Step

1. Find LCD of fractions: The LCD of 12 and 16 is 48. 2. Write as equivalent fractions with denominator of 60. $\frac{11*4}{12*4} - \frac{1*3}{16*3} = \frac{44}{48} - \frac{3}{48}$ 3. Subtract numerators. $\frac{44-3}{48} = \frac{41}{48}$
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