## Algebra: A Combined Approach (4th Edition)

$\frac{10}{9}$ tons
$m=\frac{kwh^2}{l}$ Let $m$ be the weight of the beam. Let $w$ be the width of the beam. Let $h$ be the height of the beam. Let $l$ be the length of the beam. $m=3; w=\frac{1}{3}; h=1; l=10$ $3=\frac{k\frac{1}{3}(1)^2}{10}$ $3=\frac{k}{30}$ $3\times30=\frac{k}{30}\times30$ $k=90$ $m=\frac{90wh^2}{l}$ $w=1; h=\frac{1}{3}; l=9$ $m=\frac{90(1)(\frac{1}{3})^2}{9}$ $m=\frac{90}{81}$ $m=\frac{10}{9}$ tons