Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.4 - Variation and Problem Solving - Exercise Set - Page 664: 30

Answer

$a=kbc$

Work Step by Step

Because $a$ varies jointly as $b$ and $c$, we equate $a$ to a constant multiple of $b$ and $c$: $a=kbc$.
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