Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.4 - Variation and Problem Solving - Exercise Set: 30

Answer

$a=kbc$

Work Step by Step

Because $a$ varies jointly as $b$ and $c$, we equate $a$ to a constant multiple of $b$ and $c$: $a=kbc$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.