Answer
$1.28$ tons
Work Step by Step
Let $w$ be the maximum weight a circular column can hold.
Let $h$ be the height of the circular column.
$w=\frac{k}{h^2}$
$w=2; h=8$
$2=\frac{k}{8^2}$
$2=\frac{k}{64}$
$k=128$
$w=\frac{128}{h^2}$
Finding the weight a 10-foot column can hold.
$w=\frac{128}{10^2}$
$w=\frac{128}{100}$
$w=1.28$ tons
