Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.4 - Variation and Problem Solving - Exercise Set: 12

Answer

$24$ cubic meters

Work Step by Step

$V=kT$ $V=20; T=300$ $20=k(300)$ $k=\frac{1}{15}$ $V=\frac{1}{15}T$ Volume when temperature is 360K: $V=\frac{1}{15}(360)$ $V=24$ cubic meters
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