Answer
∅ meaning no solution
Work Step by Step
System of Equations:
$2x+4y-2z=3$
$-x+y-z=6$
$x+2y-z=1$
Add equations 2 and 3 to eliminate x:
$3y-2z=7$
Multiply equation 2 by 2 and add equations 1 and 2 to eliminate x:
$6y-4z=15$
Solve the system of equation by multiplying equation 1 by 2 and subtracting equation 1 from equation 2:
The answer you will get is $0=-8$ which is not true, therefore the system of equations has no solution.
$3y-2z=7$
$6y-4z=15$
