## Algebra: A Combined Approach (4th Edition)

$8\frac{1}{8}$ inches
Let $d$ be the distance a spring stretches. Let $w$ be the weight. $d=kw$ $d=5; w=40$ $5=k(40)$ $k=\frac{1}{8}$ $d=\frac{1}{8}w$ $w=65$ $d=\frac{1}{8}(65)$ $d=\frac{65}{8}=8\frac{1}{8}$ inches