Answer
a. $f(0)=-2$
b. $f(-3)=-20$
c. $f(\frac{1}{3})=-\frac{10}{9}$
Work Step by Step
$f(x)=-x^2+3x-2$
a.
$f(0)=-(0)^2+3(0)-2$
$f(0)=-2$
b.
$f(-3)=-(-3)^2+3(-3)-2$
$f(-3)=-9-9-2$
$f(-3)=-20$
c.
$f(\frac{1}{3})=-(\frac{1}{3})^2+3(\frac{1}{3})-2$
$f(\frac{1}{3})=-\frac{1}{9}+1-2$
$f(\frac{1}{3})=-\frac{10}{9}$
