Answer
$x=\frac{1}{5}, -\frac{3}{2}, -6$
Work Step by Step
$(5x-1)(2x^2+15x+18)=0$
$(5x-1)(2x^2+12x+3x+18)=0$
$(5x-1)(2x(x+6)+3(x+6))=0$
$(5x-1)(2x+3)(x+6)=0$
$5x-1=0$
$5x=1$
$x=\frac{1}{5}$
$2x+3=0$
$2x=-3$
$x=-\frac{3}{2}$
$x+6=0$
$x=-6$