Answer
$-x^2-6x+10$
Work Step by Step
If $Q(x) = 4x^2-6x+3$ and $R(x) = 5x^2-7$
$Q(x) - R(x) = 4x^2-6x+3 - (5x^2-7) = 4x^2-6x+3-5x^2+7 = -x^2-6x+10$
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