#### Answer

y = -3x - 1

#### Work Step by Step

This problem is asking to graph a parallel line to the line 3x + y = 5, using the point (-1, 2) and to write it in slope-intercept form.
The first task is to change the equation to slope-intercept form:
(y = mx + b)
First subtract both sides by 3x to get y alone. The new equation is:
(y = -3x + 5)
By using the slope for this line, we can graph our new line. The slope is -3 and this line passes through the y-axis at (0, 5).
To find the parallel line we use the point-slope form:
(y - yx_{y}1) = m(x - xx_{y}1)
(y - 2) = -3(x + 1)
**(1 is added here because when you subtract a negative it becomes positive)
Next use the distributive property
y - 2 = -3x - 3
Then combine like terms (by adding 2 to both sides)
The parallel line is y = -3x - 1