Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.1 - Review of Equations of Lines and Writing Parallel and Perpendicular Lines - Practice: 2

Answer

Practice 2 (Solution) The slope of the line, m, is m = $\frac{(4-0)}{(-2-3)}$ = $\frac{-4}{5}$ Making use of the point-slope form and replace (x1, y1) by (3, 0) and m = $\frac{-4}{5}$, y – y1 = m (x – x1) Point-slope form y – 0 = $\frac{-4}{5}$(x – 3) Substitute (x1, y1) by (3, 0) and m = $\frac{-4}{5}$ 5y = –4 (x – 3) Simplify 5y = –4x + 12 4x + 5y = 12 In standard form, the equation is 4x + 5y = 12.

Work Step by Step

Practice 2 (Solution) The slope of the line, m, is m = $\frac{(4-0)}{(-2-3)}$ = $\frac{-4}{5}$ Making use of the point-slope form and replace (x1, y1) by (3, 0) and m = $\frac{-4}{5}$, y – y1 = m (x – x1) Point-slope form y – 0 = $\frac{-4}{5}$(x – 3) Substitute (x1, y1) by (3, 0) and m = $\frac{-4}{5}$ 5y = –4 (x – 3) Simplify 5y = –4x + 12 4x + 5y = 12 In standard form, the equation is 4x + 5y = 12.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.