Answer
$\dfrac{1}{y^2-1}$
Work Step by Step
$\dfrac{y^{-2}}{1-y^{-2}}=\dfrac{\dfrac{1}{y^2}}{1-\dfrac{1}{y^2}}=\dfrac{\dfrac{1}{y^2}}{\dfrac{y^2-1}{y^2}}=\dfrac{y^2}{y^2(y^2-1)}=\dfrac{1}{y^2-1}$
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