Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.7 - Simplifying Complex Fractions - Exercise Set - Page 549: 32

Answer

$\dfrac{\dfrac{-x+2}{18}}{\dfrac{8}{9}}=\dfrac{2-x}{16}$

Work Step by Step

$\dfrac{\dfrac{-x+2}{18}}{\dfrac{8}{9}}$ Evaluate the division and simplify: $\dfrac{\dfrac{-x+2}{18}}{\dfrac{8}{9}}=\dfrac{-x+2}{18}\div\dfrac{8}{9}=\dfrac{9(-x+2)}{18(8)}=\dfrac{-x+2}{2(8)}=\dfrac{2-x}{16}$
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