Answer
$\dfrac{\dfrac{x}{y}+1}{\dfrac{x}{y}-1}=\dfrac{x+y}{x-y}$
Work Step by Step
$\dfrac{\dfrac{x}{y}+1}{\dfrac{x}{y}-1}$
Evaluate the sum indicated in the numerator and the substraction indicated in the denominator:
$\dfrac{\dfrac{x}{y}+1}{\dfrac{x}{y}-1}=\dfrac{\dfrac{x+y}{y}}{\dfrac{x-y}{y}}=...$
Evaluate the division and simplify:
$...=\dfrac{x+y}{y}\div\dfrac{x-y}{y}=\dfrac{y(x+y)}{y(x-y)}=\dfrac{x+y}{x-y}$
