Answer
$\dfrac{-\dfrac{5}{12x^{2}}}{\dfrac{25}{16x^{3}}}=-\dfrac{4x}{15}$
Work Step by Step
$\dfrac{-\dfrac{5}{12x^{2}}}{\dfrac{25}{16x^{3}}}$
Evaluate the division and simplify:
$\dfrac{-\dfrac{5}{12x^{2}}}{\dfrac{25}{16x^{3}}}=-\dfrac{5}{12x^{2}}\div\dfrac{25}{16x^{3}}=-\dfrac{(5)(16x^{3})}{(25)(12x^{2})}=-\dfrac{(5)(16)x}{(25)(12)}=...$
$...=-\dfrac{16x}{5(12)}=-\dfrac{4x}{15}$