Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.6 - Proportions and Problem Solving with Rational Equations - Exercise Set: 30

Answer

The room can accommodate up to 26 students

Work Step by Step

Dimensions are: 20-foot by 12-foot Thus area of room = 20(12) = 240 square feet. Since every student needs a minimum of 9 square feet, total students that can be accommodate are : $\frac{240}{9}$ = 26.667. But, students cannot be in fractions, thus the nearest number lower than 26.667 is 26. Thus the room can accommodate 26 students.
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