## Algebra: A Combined Approach (4th Edition)

Let the number be $\rightarrow$ x Thus twice that number added to three = 2x + 3 Number plus 1 = x + 1. Three halves = $\frac{1}{2}$ + $\frac{1}{2}$ + $\frac{1}{2}$ = $\frac{3}{2}$ Given : $\frac{(2x + 3)}{(x + 1)}$ = $\frac{3}{2}$ Thus, 2(2x + 3) = 3(x + 1) 4x + 6 = 3x + 3 4x - 3x + 6 - 6= 3x - 3x + 3 - 6 .....( Subtract 3x and 6 on both sides) 4x - 3x = 3 - 6 x = -3