Answer
$ \dfrac{3x^2+5x+3}{(3x-1)^2}$
Work Step by Step
$\dfrac{x+2}{3x-1}+\dfrac{5}{(3x-1)^2}$ is a rational expression
$\dfrac{x+2}{3x-1}+\dfrac{5}{(3x-1)^2} = \dfrac{(x+2)(3x-1)^2+5(3x-1)}{(3x-1)(3x-1)^2} = \dfrac{(3x-1)[(x+2)(3x-1)+5]}{(3x-1)(3x-1)^2} = \dfrac{(x+2)(3x-1)+5}{(3x-1)^2} = \dfrac{3x^2-x+6x-2+5}{(3x-1)^2} = \dfrac{3x^2+5x+3}{(3x-1)^2}$