Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set: 66

Answer

$\frac{9}{4(x-1)}$

Work Step by Step

$\frac{9}{x^{2}-1}$ $\div$ $\frac{12}{3x+3}$= $\frac{9}{(x+1)(x-1)}$ $\times$ $\frac{3x+3}{12}$= $\frac{9}{(x+1)(x-1)}$ $\times$ $\frac{3(x+1)}{12}$= $\frac{9*3(x+1)}{(x+1)(x-1)12}$ =$\frac{27}{12(x-1)}$= $\frac{9}{4(x-1)}$
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