Answer
$\frac{9}{x+4}$
Work Step by Step
$\frac{8}{x+4}$-$\frac{3}{3x+12}$
$\frac{8}{x+4}$-$\frac{3}{3(x+4)}$=
$\frac{8*3}{(x+4)*3}$+$\frac{3}{3*(x+4)}$=
$\frac{24+3}{3(x+4)}$=$\frac{27}{3(x+4)}$=
$\frac{9}{x+4}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 515: 8
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