Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set: 8

Answer

$\frac{9}{x+4}$

Work Step by Step

$\frac{8}{x+4}$-$\frac{3}{3x+12}$ $\frac{8}{x+4}$-$\frac{3}{3(x+4)}$= $\frac{8*3}{(x+4)*3}$+$\frac{3}{3*(x+4)}$= $\frac{24+3}{3(x+4)}$=$\frac{27}{3(x+4)}$= $\frac{9}{x+4}$
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