Answer
$\frac{6x-7}{x-2}$
Work Step by Step
$\frac{5}{x-2}$+6
=$\frac{5}{x-2}$+ $\frac{6(x-2)}{x-2}$
= $\frac{5+6(x-2)}{x-2}$
=$\frac{5+6x-12}{x-2}$
= $\frac{6x-7}{x-2}$
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