Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 515: 13

Answer

$\frac{-2}{x-3}$

Work Step by Step

$\frac{6}{x-3}$+$\frac{8}{3-x}$= $\frac{6}{x-3}$+$\frac{8(-1)}{(3-x)(-1)}$= $\frac{6}{x-3}$+$\frac{-8}{x-3}$= $\frac{6-8}{x-3}$=$\frac{-2}{x-3}$
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