Answer
$\frac{-2}{x-3}$
Work Step by Step
$\frac{6}{x-3}$+$\frac{8}{3-x}$=
$\frac{6}{x-3}$+$\frac{8(-1)}{(3-x)(-1)}$=
$\frac{6}{x-3}$+$\frac{-8}{x-3}$=
$\frac{6-8}{x-3}$=$\frac{-2}{x-3}$
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