Answer
$\frac{4(x+2)}{7x(3x-1)}$
Work Step by Step
$\frac{4x+8}{7x^2-14x}\times \frac{3x^2-5x-2}{9x^2-1}$
$=\frac{4(x+2)}{7x(x-2)}\times \frac{(3x+1)(x-2)}{(3x+1)(3x-1)}$
$=\frac{4(x+2)}{7x}\times \frac{1}{(3x-1)}$
$=\frac{4(x+2)}{7x(3x-1)}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Practice - Page 494: 3
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