Answer
a. $\frac{16y}{3x^2}$
b. $\frac{-2a^2}{9b}$
Work Step by Step
a.
$\frac{16y}{3}\times\frac{1}{x^2}$
$=\frac{16y\times1}{3\times x^2}$
$=\frac{16y}{3x^2}$
b.
$\frac{-5a^3}{3b^3}\times\frac{2b^2}{15a}$
$=\frac{-5a^3\times 2b^2}{3b^3\times 15a}$
$=\frac{-10a^3b^2}{45ab^3}$
$=\frac{-2a^2}{9b}$
