Answer
$\dfrac{3x+6}{20}\div\dfrac{4x+8}{8}=\dfrac{3}{5}$
Work Step by Step
$\dfrac{3x+6}{20}\div\dfrac{4x+8}{8}$
Take out common factor $3$ from the numerator of the first fraction and common factor $4$ from the numerator of the second fraction:
$\dfrac{3x+6}{20}\div\dfrac{4x+8}{8}=\dfrac{3(x+2)}{20}\div\dfrac{4(x+2)}{8}=...$
Evaluate the division of the two rational expressions and simplify by removing the factors that appear both in the numerator and the denominator:
$...=\dfrac{24(x+2)}{40(x+2)}=\dfrac{24}{40}=\dfrac{3}{5}$
