Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set: 34

Answer

$\dfrac{3x^{2}+12x}{6}\cdot\dfrac{9}{2x+8}=\dfrac{9x}{4}$

Work Step by Step

$\dfrac{3x^{2}+12x}{6}\cdot\dfrac{9}{2x+8}$ Take out common factor $3x$ from the numerator of the first fraction and common factor $2$ from the denominator of the second fraction: $\dfrac{3x^{2}+12x}{6}\cdot\dfrac{9}{2x+8}=\dfrac{3x(x+4)}{6}\cdot\dfrac{9}{2(x+4)}=...$ Evaluate the product of the two rational expressions and simplify by removing repeated factors in the numerator and the denominator: $...=\dfrac{27x(x+4)}{12(x+4)}=\dfrac{27x}{12}=\dfrac{9x}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.