# Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set: 33

$\dfrac{x^{2}+5x}{8}\cdot\dfrac{9}{3x+15}=\dfrac{3x}{8}$

#### Work Step by Step

$\dfrac{x^{2}+5x}{8}\cdot\dfrac{9}{3x+15}$ Take out common factor $x$ from the numerator of the first fraction and common factor $3$ from the denominator of the second fraction: $\dfrac{x^{2}+5x}{8}\cdot\dfrac{9}{3x+15}=\dfrac{x(x+5)}{8}\cdot\dfrac{9}{3(x+5)}=...$ Evaluate the product of the two rational expressions and then simplify by removing repeated factors in the numerator and the denominator: $...=\dfrac{9x(x+5)}{24(x+5)}=\dfrac{9x}{24}=\dfrac{3x}{8}$

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