Answer
$\dfrac{6x+6}{5}\div\dfrac{9x+9}{10}=\dfrac{4}{3}$
Work Step by Step
$\dfrac{6x+6}{5}\div\dfrac{9x+9}{10}$
Take out common factor $6$ from the numerator of the first fraction and common factor $9$ from the numerator of the second fraction:
$\dfrac{6x+6}{5}\div\dfrac{9x+9}{10}=\dfrac{6(x+1)}{5}\div\dfrac{9(x+1)}{10}=...$
Evaluate the division of the two rational expressions and simplify by removing repeated factors in the numerator and the denominator:
$...=\dfrac{60(x+1)}{45(x+1)}=\dfrac{60}{45}=\dfrac{4}{3}$