Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set - Page 500: 32

Answer

$\dfrac{6x+6}{5}\div\dfrac{9x+9}{10}=\dfrac{4}{3}$

Work Step by Step

$\dfrac{6x+6}{5}\div\dfrac{9x+9}{10}$ Take out common factor $6$ from the numerator of the first fraction and common factor $9$ from the numerator of the second fraction: $\dfrac{6x+6}{5}\div\dfrac{9x+9}{10}=\dfrac{6(x+1)}{5}\div\dfrac{9(x+1)}{10}=...$ Evaluate the division of the two rational expressions and simplify by removing repeated factors in the numerator and the denominator: $...=\dfrac{60(x+1)}{45(x+1)}=\dfrac{60}{45}=\dfrac{4}{3}$
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