Answer
$\dfrac{5x-10}{12}\div\dfrac{4x-8}{8}=\dfrac{5}{6}$
Work Step by Step
$\dfrac{5x-10}{12}\div\dfrac{4x-8}{8}$
Take out common factor $5$ from the numerator of the first fraction and common factor $4$ from the numerator of the second fraction:
$\dfrac{5x-10}{12}\div\dfrac{4x-8}{8}=\dfrac{5(x-2)}{12}\div\dfrac{4(x-2)}{8}=...$
Evaluate the division of the two rational expressions and simplify by removing repeated factors in the numerator and the denominator:
$...=\dfrac{40(x-2)}{48(x-2)}=\dfrac{40}{48}=\dfrac{5}{6}$