## Algebra: A Combined Approach (4th Edition)

Answer is correct. $\frac{x+2}{-8x-1}$
Answer is correct. $\frac{2-15x-8x^{2}}{64x^{2}-1}$= $\frac{2+x-16x-8x^{2}}{64x^{2}-1}$= $\frac{1(2+x)-8x(2+x)}{(8x)^{2}-1^{2}}$= $\frac{(1-8x)(2+x)}{(8x)^{2}-1^{2}}$= $\frac{(1-8x)(2+x)}{(8x+1)(8x-1)}$= $\frac{(1-8x)(2+x)}{(8x+1)(-1)(1-8x)}$= $\frac{(2+x)}{(8x+1)(-1)}$= $\frac{x+2}{-8x-1}$