Answer
$\frac{y+1}{y+2}$
Work Step by Step
$\frac{2xy+2x-3y-3}{2xy+4x-3y-6}$=
$\frac{2x(y+1)-3(y+1)}{2x(y+2)-3(y+2)}$=
$\frac{(2x-3)(y+1)}{(2x-3)(y+2)}$=
$\frac{y+1}{y+2}$
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