Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review - Page 560: 71

Answer

$a=\dfrac{1}{2}$

Work Step by Step

$\dfrac{4}{a-1}+2=\dfrac{3}{a-1}$ Multiply the whole equation by $a-1$: $(a-1)\Big(\dfrac{4}{a-1}+2=\dfrac{3}{a-1}\Big)$ $4+2(a-1)=3$ Solve for $a$: $4+2a-2=3$ $2a+2=3$ $2a=3-2$ $2a=1$ $a=\dfrac{1}{2}$ Since the initial equation is not undefined for this value of $a$, we have found the answer. The solution to this equation is $a=\dfrac{1}{2}$
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