## Algebra: A Combined Approach (4th Edition)

$\dfrac{y}{2y+2}+\dfrac{2y-16}{4y+4}=\dfrac{y-3}{y+1}$ Factor the first and second rational expressions completely: $\dfrac{y}{2(y+1)}+\dfrac{2(y-8)}{4(y+1)}=\dfrac{y-3}{y+1}$ Multiply the whole equation by $(2)(4)(y+1)$: $(2)(4)(y+1)\Big[\dfrac{y}{2(y+1)}+\dfrac{2(y-8)}{4(y+1)}=\dfrac{y-3}{y+1}\Big]$ $4y+2(y-8)(2)=(y-3)(2)(4)$ $4y+4y-32=8y-24$ Take all terms to the left side of the equation: $4y+4y-32-8y+24=0$ $-8\ne0$ This equation has no solution