Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Test - Page 478: 29

Answer

The dimension of the rectangle is 9 units (length) by 6 units (width).

Work Step by Step

Area of Rectangle = Length x Width 54 = $(x + 2)(x - 1)$ $x^2 + x - 2 - 54 = 0$ $x^2 + x - 56 = 0$ $(x + 8)(x - 7) = 0$ $x = 7$ or $x = -8$ (rejected) Therefore, x = 7 The length and width of the rectangle is $7 + 2 = 9$ units and $7 - 1 = 6$ units respectively. The dimension of the rectangle is 9 units (length) by 6 units (width).
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