Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Test - Page 478: 23

Answer

$t = - 3$ OR $ t = 5$

Work Step by Step

$t^2-2t - 15 = 0$ $t^2 - 5t + 3t - 15 = 0$ $t(t-5) + 3 (t - 5)=0$ $(t+3)(t-5) = 0$ Therefore $t + 3 = 0$ OR $t - 5 = 0$ $t = - 3$ OR $ t = 5$
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