Answer
a) Please see the table.
b) 5 seconds
c) approximately 304 feet
Work Step by Step
a)
$x=0$
$y=-16x^2+20x+300$
$y=-16*0^2+20*0+300$
$y=0+0+300 = 300$
$x=1$
$y=-16x^2+20x+300$
$y=-16*1^2+20*1+300$
$y=-16+20+300$
$y=304$
$x=2$
$y=-16x^2+20x+300$
$y=-16*2^2+20*2+300$
$y=-16*4+40+300$
$y=-64+340$
$y=276$
$x=3$
$y=-16x^2+20x+300$
$y=-16*3^2+20*3+300$
$y=-16*9+60+300$
$y=-144+360$
$y=216$
$x=4$
$y=-16x^2+20x+300$
$y=-16*4^2+20*4+300$
$y=-16*16+380$
$y=-196+380$
$y=184$
$x=5$
$y=-16x^2+20x+300$
$y=-16*5^2+20*5+300$
$y=-16*25+400$
$y=-400+400$
$y=0$
$x=6$
$y=-16x^2+20x+300$
$y=-16*6^2+20*6+300$
$y=-16*36+120+300$
$y=-576+420$
$y=-156$
b)
The ground has a height of 0, and we are at that height at $x=5$
c)
The maximum value for the height was 304 feet (at 2 seconds)