Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set: 34

Answer

The solutions are $\frac{-1}{4}$ and 3.

Work Step by Step

x(4x-11)=3 4$x^{2}$-11x=3 4$x^{2}$-11x-3=3-3 4$x^{2}$-11x-3=0 4$x^{2}$-12x+1x-3=0 4x(x-3)+1(x-3)=0 (4x+1)(x-3)=0 4x+1=0 x-3=0 4x+1-1=0-1 or x-3+3=0+3 4x=-1 or x=3 $\frac{4x}{4}$ =$\frac{-1}{4}$ or x=3 x=$\frac{-1}{4}$ or x=3 The solutions are $\frac{-1}{4}$ and 3. Check Let x=-$\frac{1}{4}$ x(4x-11)=3 -$\frac{1}{4}$[-$\frac{1}{4}$4-11]=3 -$\frac{1}{4}$(-1-11)=3 -$\frac{1}{4}$(-12)=3 3=3 Let x=3 x(4x-11)=3 3(4*3-11)=3 3(12-11)=3 3*1=3 3=3
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