Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 457: 26

Answer

The solutions are 0 and -15.

Work Step by Step

$x^{2}$+15x=0 x(x+15)=0 x=0 or x+15=0 x=0 or x+15-15=0-15 x=0 or x=-15 The solutions are 0 and -15. Check Let x=0 $x^{2}$+15x=0 $0^{2}$ +15*0=0 0=0 Let x=-15 $x^{2}$+20x=0 $(-15)^{2}$ +15(-15)=0 225-225=0 0=0
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