Answer
The solutions are -$\frac{2}{9}$ and $\frac{1}{4}$.
Work Step by Step
(x+$\frac{2}{9}$)(x-$\frac{1}{4}$)=0
x-$\frac{1}{4}$ =0 or x+$\frac{2}{9}$=0
x-$\frac{1}{4}$+$\frac{1}{4}$ =0 +$\frac{1}{4}$
or
x+$\frac{2}{9}$-$\frac{2}{9}$=0-$\frac{2}{9}$
x=-$\frac{2}{9}$ or x=$\frac{1}{4}$
The solutions are -$\frac{2}{9}$ and $\frac{1}{4}$.
check $\frac{1}{4}$
(x+$\frac{2}{9}$)(x-$\frac{1}{4}$)=0
($\frac{1}{4}$+$\frac{2}{9}$)($\frac{1}{4}$-$\frac{1}{4}$)=0
($\frac{1}{4}$+$\frac{2}{9}$)0=0
0=0
Let x= $\frac{-2}{9}$
(x+$\frac{2}{9}$)(x-$\frac{1}{4}$)=0
($\frac{-2}{9}$ +$\frac{2}{9}$)($\frac{-2}{9}$ -$\frac{1}{4}$)=0
0($\frac{-2}{9}$ -$\frac{1}{4}$)=0
0=0
