Answer
The solutions are $\frac{3}{4}$ and $\frac{-1}{9}$.
Work Step by Step
(9x+1)(4x-3)=0
4x-3=0 or 9x+1=0
4x-3+3=0+3 or 9x+1-1=0-1
4x=3 or 9x=-1
$\frac{4x}{4}$=$\frac{3}{4}$ or $\frac{9x}{9}$=$\frac{-1}{9}$
x=$\frac{3}{4}$ or x=$\frac{-1}{9}$
The solutions are $\frac{3}{4}$ and $\frac{-1}{9}$.
check
Let x=$\frac{3}{4}$
(9x+1)(4x-3)=0
(9$\frac{3}{4}$ +1)(4$\frac{3}{4}$ -3)=0
(9$\frac{3}{4}$ +1)(3 -3)=0
(9$\frac{3}{4}$ +1)0=0
0=0
Let x= $\frac{-1}{9}$
(9x+1)(4x-3)=0
[9$\frac{(-1)}{9}$+1][4($\frac{-1}{9}$)-3]=0
(-1+1)[4($\frac{-1}{9}$)-3]=0
0)[4($\frac{-1}{9}$)-3]=0
0=0
