Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.4 - Factoring Trinomials of the Form ax2+bx+c by Grouping - Exercise Set - Page 441: 35

Answer

$a*(4a+1)(5a+8)$

Work Step by Step

$20a^3+37a^2+8a$ $a*(20a^2+37a+8)$ $20a^2+37a+8$ $20a^2+32a+5a+8$ $4a(5a+8)+5a+8$ $4a(5a+8)+1(5a+8)$ $(4a+1)(5a+8)$ $a*(4a+1)(5a+8)$
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