Chapter 6 - Section 6.3 - Factoring Trinomials of the Form ax2+bx+c - Practice - Page 433: 5

$(2x^2-7)(x^2+1)$

$2x^4-5x^2-7$ Factors of -7: 1 and -7, -1 and 7 $(2x^2+1)(x^2-7)$ $2x^2*x^2+(-7)*2x^2+1*2x^2+1*(-7)$ $2x^4-14x^2+2x^2-7$ $2x^4-12x^2-7$ (wrong middle term) $(2x^2-7)(x^2+1)$ $2x^2*x^2+2x^2*1-7*x^2-7*1$ $2x^4+2x^2-7x^2-7$ $2x^4-5x^2-7$