Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.3 - Factoring Trinomials of the Form ax2+bx+c - Exercise Set: 13

Answer

$(4r-1)(5r+8)$

Work Step by Step

$20r^2+27r-8$ $20 \times -8=-160$ Factors of $-160$; Sum should $=27$ $32 \times -5$; Sum $=27$ $20r^2+32r-5r-8$ $=4r(5r+8)-1(5r+8)$ $=(4r-1)(5r+8)$
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