Chapter 6 - Section 6.1 - The Greatest Common Factor - Exercise Set - Page 422: 85

$2,6$

lets call the numbers $x, y$ $x+y = 8$ $x\times y = 12$ $x+y = 8$ Therefore $x=8- y$ $x\times y =12$ Therefore $(8-y)\times y = 12$ $8y - y^2 = 12$ $ - y^2 + 8y - 12= 0$ $ - (y - 6) (y-2)$ $ y = 6, 2$ $x = 2, 6$ Therefore the numbers are $2,6$