Answer
$20,22$
Work Step by Step
let's call the first number $x$, and the second will be $x+2$
We know that
$x(x+2) = 440$
$x^2 + 2x - 440= 0$
$x^2 + 22 x - 20x - 440= 0$
$x(x+22) - 20 (x + 22) = 0$
$(x-20)(x+22) = 0$
And because we know x should be a positive even integer.
$x = 20, x \ne -22$
Therefore the numbers ae
$20,22$
