Answer
$2xy - 4 + \frac{1}{2y}$
Work Step by Step
$\frac{8x^2y^2 - 16xy + 2x}{4xy}$
$=\frac{8x^2y^2}{4xy} - \frac{16xy}{4xy} + \frac{2x}{4xy}$
$=2xy - 4 + \frac{1}{2y}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 6 - Cumulative Review - Page 480: 41
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